Confusing pretty print for method call on if expression

[fhackett]

import quoted.Toolbox.Default._
val v = '{ (if true then Some(1) else None).map(v => v+1) }
v.show

will output (in REPL, Dotty 0.12.0):

val res0: String = if (true) scala.Some.apply[scala.Int](1) else scala.None.map[scala.Int](((v: scala.Int) => v.+(1)))
...

The confusing part is scala.None.map[scala.Int](..., which unless closely inspected suggests that we are calling None.map instead of (if ...).map.

Perhaps adding brackets around if expressions that are in this situation (the LHS of a method call) might help?

[nicolasstucki]

It is clearly missing a pair of ( and ) around the if then else

It should print

val res0: String = (if (true) scala.Some.apply[scala.Int](1) else scala.None).map[scala.Int](((v: scala.Int) => v.+(1)))