OrderedSet.index(...) function throws error when key is a frozenset

[KSneijders]

I'm unable to use OrderedSet.index(...) function with frozensets as values. It throws an error when the key is a frozenset.

Code to recreate the error:

os = OrderedSet([frozenset([1, 2])])
i = os.index(frozenset([1, 2]))

Traceback (most recent call last):
  File "<PATH>\src\main.py", line 11, in <module>
    i = os.index(frozenset([1, 2]))
        ^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "<PATH>\Python311\Lib\site-packages\ordered_set\__init__.py", line 246, in index
    return [self.index(subkey) for subkey in key]
           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "<PATH>\Python\Python311\Lib\site-packages\ordered_set\__init__.py", line 246, in <listcomp>
    return [self.index(subkey) for subkey in key]
            ^^^^^^^^^^^^^^^^^^
  File "<PATH>\Python\Python311\Lib\site-packages\ordered_set\__init__.py", line 247, in index
    return self.map[key]
           ~~~~~~~~^^^^^
KeyError: 1

Thanks for this amazing utility!

[KSneijders]

@rspeer Hey, sorry for the ping- is this package still in 'active' development? 🙂