fix: Show independent tasks in the table

[mgmacias95]

Having a script with two independent event loops, only one of them is displayed in the table. This PR fixes that.

import asyncio
import threading

async def factorial(name, number):
    f = 1
    for i in range(2, number + 1):
        print(f"Task {name}: Compute factorial({number}), currently i={i}...")
        await asyncio.sleep(1)
        f *= i
    print(f"Task {name}: factorial({number}) = {f}")
    return f

async def main():
    # Schedule three calls *concurrently*:
    L = await asyncio.gather(
        factorial("A", 200),
        factorial("B", 300),
        factorial("C", 400),
    )
    print(L)

async def main2():
    await asyncio.sleep(100)


t1 = threading.Thread(target=asyncio.run, args=(main(),))
t2 = threading.Thread(target=asyncio.run, args=(main2(),))

t1.start()
t2.start()
t1.join()
t2.join()