infchan

Exposes a generic, unbounded channel.

Usage Example

c := infchan.NewChannel[int]()

for i := 0; i < 100; i++ {
    c.In() <- i
}
c.Close()

sum := 0
for n := range c.Out() {
    sum += n
}

test.That(t, sum, is.EqualTo(4950))

Notes

When the consuming side of a channel is processing slower than the producing side, bad things happen. These bad things are unavoidable, but we can decide what flavor of "bad thing" we'd like to deal with!

The native buffered channel in Go will cause sends to block when the buffer is full.

The channel exposed in this implementation will continously accept and buffer sends until the application runs out of memory.

Carefully consider which one of these you'd prefer - you may find that your problem actually lies elsewhere.