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List.foldl
List.foldr
問題点として、本文で挙げられている List.sum 関数などは List.foldl の例として紹介されているが、実際には List.foldr の方と definitionally equal になっている。
List.sum
example : List.foldr (f := (· + ·)) (init := 0) = List.sum := by rfl
The text was updated successfully, but these errors were encountered:
List.foldl と List.foldr の説明が不適当
7671f25
Fixes #923
Seasawher
Successfully merging a pull request may close this issue.
問題点として、本文で挙げられている
List.sum
関数などはList.foldl
の例として紹介されているが、実際にはList.foldr
の方と definitionally equal になっている。The text was updated successfully, but these errors were encountered: