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Ccurrently I = I_S * exp(V/(n*V_T)) is used. I = I_S * (exp(V/(n*V_T)) - 1) is much more appropriate.
I = I_S * exp(V/(n*V_T))
I = I_S * (exp(V/(n*V_T)) - 1)
Furthermore, the log-linear least squares focuses too much on minimizing the error around 0.
The text was updated successfully, but these errors were encountered:
#5 Proper Shockley diode model
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Ccurrently
I = I_S * exp(V/(n*V_T))
is used.I = I_S * (exp(V/(n*V_T)) - 1)
is much more appropriate.Furthermore, the log-linear least squares focuses too much on minimizing the error around 0.
The text was updated successfully, but these errors were encountered: