Edit pass flake8 requirements for PR savoirfairelinux#555, Fix error …

…Korean ordinal conversion
dogzz9445 · Feb 3, 2024 · 0ac94f0 · 0ac94f0
1 parent 5670f76
commit 0ac94f0
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Showing 2 changed files with 10 additions and 8 deletions.
diff --git a/num2words/lang_KO.py b/num2words/lang_KO.py
@@ -22,6 +22,7 @@
 
 import re
 
+
 class Num2Word_KO(Num2Word_Base):
     CURRENCY_FORMS = {
         'KRW': ('원', None),
@@ -79,7 +80,7 @@ def setup(self):
                      "칠십": "일흔",
                      "팔십": "여든",
                      "구십": "아흔"}
-        
+
     def merge(self, lpair, rpair):
         ltext, lnum = lpair
         rtext, rnum = rpair
@@ -96,7 +97,8 @@ def to_ordinal(self, value):
         self.verify_ordinal(value)
         outwords = self.to_cardinal(value).split(" ")
         if value % 100 != 0:
-            re_mid_words = '|'.join('(?<={})'.format(re.escape(delim)) for delim in ['천', '백'])
+            re_mid_words = '|'.join('(?<={})'.format(re.escape(delim)) 
+                for delim in ['천', '백'])
             lastwords = re.split(re_mid_words, outwords[-1])
             if "십" in lastwords[-1]:
                 ten_one = lastwords[-1].split("십")

diff --git a/tests/test_ko.py b/tests/test_ko.py
@@ -83,12 +83,12 @@ def test_currency(self):
 
     def test_ordinal(self):
         cases = [(1, "한"), (101, "백한"), (2, "두"), (5, "다섯"), (1050, "천쉰"),
-                 (10, "열"), (20, "스무"), (21, "스물한"), (100, "백"), (1000, "천"), 
-                 (10000, "만"), (100000, "십만"), (1000000, "백만"),  (100001, "십만 한"),
-                 (10000000, "천만"), (100000000, "일억"), (1000000000, "십억"),
-                 (10000000000, "백억"), (100000000000, "천억"),
-                 (1000000000000, "일조"), (10000000000000, "십조"),
-                 (25, "스물다섯"), (137, "백서른일곱")]
+                 (10, "열"), (20, "스무"), (21, "스물한"), (100, "백"),
+                 (1000, "천"), (10000, "만"), (100000, "십만"), (1000000, "백만"),
+                 (100001, "십만 한"),(10000000, "천만"), (100000000, "일억"),
+                 (1000000000, "십억"),(10000000000, "백억"),
+                 (100000000000, "천억"), (1000000000000, "일조"),
+                 (10000000000000, "십조"), (25, "스물다섯"), (137, "백서른일곱")]
         for num, out in cases:
             self.assertEqual(n2k(num, to="ordinal"), out)