Go parser for maven Project Object Model (POM) file
Let's take the following POM file
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.example</groupId>
<artifactId>my-app</artifactId>
<version>1.0.0-SNAPSHOT</version>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<scope>test</scope>
</dependency>
<dependency>
<groupId>javax.enterprise</groupId>
<artifactId>cdi-api</artifactId>
<scope>provided</scope>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.8.0</version>
<configuration>
<release>11</release>
</configuration>
</plugin>
</plugins>
</build>
</project>
You can read the pom file using
package main
import (
"github.com/creekorful/mvnparser"
"encoding/xml"
"log"
)
func main() {
// filled with previously declared xml
pomStr := "..."
// Load project from string
var project mvnparser.MavenProject
if err := xml.Unmarshal([]byte(pomStr), &project); err != nil {
log.Fatalf("unable to unmarshal pom file. Reason: %s", err)
}
log.Print(project.GroupId) // -> com.example
log.Print(project.ArtifactId) // -> my-app
log.Print(project.Version) // -> 1.0.0-SNAPSHOT
// iterate over dependencies
for _, dep := range project.Dependencies {
log.Print(dep.GroupId)
log.Print(dep.ArtifactId)
log.Print(dep.Version)
// ...
}
}