xmlquery
is an XPath query package for XML documents, allowing you to extract
data or evaluate from XML documents with an XPath expression.
xmlquery
has a built-in query object caching feature that caches recently used
XPATH query strings. Enabling caching can avoid recompile XPath expression for
each query.
You can visit this page to learn about the supported XPath(1.0/2.0) syntax. https://github.com/antchfx/xpath
htmlquery - Package for the HTML document query.
xmlquery - Package for the XML document query.
jsonquery - Package for the JSON document query.
$ go get github.com/antchfx/xmlquery
import (
"github.com/antchfx/xmlquery"
)
func main(){
s := `<?xml version="1.0" encoding="UTF-8" ?>
<rss version="2.0">
<channel>
<title>W3Schools Home Page</title>
<link>https://www.w3schools.com</link>
<description>Free web building tutorials</description>
<item>
<title>RSS Tutorial</title>
<link>https://www.w3schools.com/xml/xml_rss.asp</link>
<description>New RSS tutorial on W3Schools</description>
</item>
<item>
<title>XML Tutorial</title>
<link>https://www.w3schools.com/xml</link>
<description>New XML tutorial on W3Schools</description>
</item>
</channel>
</rss>`
doc, err := xmlquery.Parse(strings.NewReader(s))
if err != nil {
panic(err)
}
channel := xmlquery.FindOne(doc, "//channel")
if n := channel.SelectElement("title"); n != nil {
fmt.Printf("title: %s\n", n.InnerText())
}
if n := channel.SelectElement("link"); n != nil {
fmt.Printf("link: %s\n", n.InnerText())
}
for i, n := range xmlquery.Find(doc, "//item/title") {
fmt.Printf("#%d %s\n", i, n.InnerText())
}
}
list, err := xmlquery.QueryAll(doc, "a")
if err != nil {
panic(err)
}
doc, err := xmlquery.LoadURL("http://www.example.com/sitemap.xml")
s := `<?xml version="1.0" encoding="utf-8"?><rss version="2.0"></rss>`
doc, err := xmlquery.Parse(strings.NewReader(s))
f, err := os.Open("../books.xml")
doc, err := xmlquery.Parse(f)
f, err := os.Open("../books.xml")
p, err := xmlquery.CreateStreamParser(f, "/bookstore/book")
for {
n, err := p.Read()
if err == io.EOF {
break
}
if err != nil {
...
}
}
f, err := os.Open("../books.xml")
p, err := xmlquery.CreateStreamParser(f, "/bookstore/book", "/bookstore/book[price>=10]")
for {
n, err := p.Read()
if err == io.EOF {
break
}
if err != nil {
...
}
}
list := xmlquery.Find(doc, "//book//author")
// or
list := xmlquery.Find(doc, "//author")
book := xmlquery.FindOne(doc, "//book[2]")
list := xmlquery.Find(doc,"//book/@id")
list := xmlquery.Find(doc, "//book[@id='bk104']")
list := xmlquery.Find(doc, "//book[price<5]")
expr, err := xpath.Compile("sum(//book/price)")
price := expr.Evaluate(xmlquery.CreateXPathNavigator(doc)).(float64)
fmt.Printf("total price: %f\n", price)
expr, err := xpath.Compile("count(//book)")
price := expr.Evaluate(xmlquery.CreateXPathNavigator(doc)).(float64)
Find
and QueryAll
both do the same thing: searches all of matched XML nodes.
Find
panics if provided with an invalid XPath query, while QueryAll
returns
an error.
Yes, you can. We provide QuerySelector
and QuerySelectorAll
methods; they
accept your query expression object.
Caching a query expression object avoids recompiling the XPath query expression, improving query performance.
doc := &xmlquery.Node{
Type: xmlquery.DeclarationNode,
Data: "xml",
Attr: []xml.Attr{
xml.Attr{Name: xml.Name{Local: "version"}, Value: "1.0"},
},
}
root := &xmlquery.Node{
Data: "rss",
Type: xmlquery.ElementNode,
}
doc.FirstChild = root
channel := &xmlquery.Node{
Data: "channel",
Type: xmlquery.ElementNode,
}
root.FirstChild = channel
title := &xmlquery.Node{
Data: "title",
Type: xmlquery.ElementNode,
}
title_text := &xmlquery.Node{
Data: "W3Schools Home Page",
Type: xmlquery.TextNode,
}
title.FirstChild = title_text
channel.FirstChild = title
fmt.Println(doc.OutputXML(true))
// <?xml version="1.0"?><rss><channel><title>W3Schools Home Page</title></channel></rss>
fmt.Println(doc.OutputXMLWithOptions(WithOutputSelf()))
// <?xml version="1.0"?><rss><channel><title>W3Schools Home Page</title></channel></rss>
Please let me know if you have any questions