Fix typos and update hyperlinks

docs/src/devdocs/evaluating_loops.md

@@ -1,6 +1,6 @@
 # Determining the strategy for evaluating loops
 
-The heart of the optimizatizations performed by LoopVectorization are given in the [determinestrategy.jl](https://github.com/JuliaSIMD/LoopVectorization.jl/blob/master/src/determinestrategy.jl) file utilizing instruction costs specified in [costs.jl](https://github.com/JuliaSIMD/LoopVectorization.jl/blob/master/src/costs.jl).
+The heart of the optimizations performed by LoopVectorization are given in the [determinestrategy.jl](https://github.com/JuliaSIMD/LoopVectorization.jl/blob/master/src/modeling/determinestrategy.jl) file utilizing instruction costs specified in [costs.jl](https://github.com/JuliaSIMD/LoopVectorization.jl/blob/master/src/modeling/costs.jl).
 Essentially, it estimates the cost of different means of evaluating the loops. It iterates through the different possible loop orders, as well as considering which loops to unroll, and which to vectorize. It will consider unrolling 1 or 2 loops (but it could settle on unrolling by a factor of 1, i.e. not unrolling), and vectorizing 1.
 
 The cost estimate is based on the costs of individual instructions and the number of times each one needs to be executed for the given strategy. The instruction cost can be broken into several components:
@@ -14,7 +14,7 @@ Data on individual instructions for specific architectures can be found on [Agne
 Examples of how these come into play:
 - Vectorizing a loop will result in each instruction evaluating multiple iterations, but the costs of loads and stores will change based on the memory layouts of the accessed arrays.
 - Unrolling can help reduce the number of times an operation must be performed, for example if it can allow us to reuse memory multiple times rather than reloading it every time it is needed.
-- When there is a reduction, such as performing a sum, there is a dependency chain. Each `+` has to wait for the previous `+` to finish executing before it can begin, thus execution time is bounded by latency rather than minimum of the throughput of the `+` and load operations. By unrolling the loop, we can create multiple independent dependency chains.
+- When there is a reduction, such as performing a sum, there is a dependency chain. Each `+` has to wait for the previous `+` to finish executing before it can begin, thus execution time is bounded by latency rather than the minimum of the throughput of the `+` and load operations. By unrolling the loop, we can create multiple independent dependency chains.