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find-first-and-last-position-of-element-in-sorted-array.js
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find-first-and-last-position-of-element-in-sorted-array.js
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// Source: https://leetcode.com/problems/find-first-and-last-position-of-element-in-sorted-array/
// Difficulty: Medium
/**
* Search index for target 5 in array like [1,2,3,4,5,5]
* At least, the end element is equal to target
*
* @param {number[]} nums
* @param {number} start
* @param {number} end
* @param {number} target
*/
const searchEnd = (nums, start, end, target) => {
while (start < end) {
const mid = Math.floor((start + end) / 2);
if (nums[mid] === target) {
end = mid;
} else {
start = mid + 1;
}
}
return end;
};
/**
* Search end index target 1 in array like [1,1,2,3,4]
* At least the first element is equal to target
*
* @param {number[]} nums
* @param {number} start
* @param {number} end
* @param {number} target
*/
const searchStart = (nums, start, end, target) => {
while (start < end) {
// This one should use ceil instead of floor
// To avoid infinite loop when there are 2 elements
const mid = Math.ceil((start + end) / 2);
if (nums[mid] === target) {
start = mid;
} else {
end = mid - 1;
}
}
return start;
};
/**
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
const searchRange = (nums, target) => {
let start = 0;
let end = nums.length - 1;
while (start <= end) {
const mid = Math.floor((start + end) / 2);
if (nums[mid] === target) {
return [
searchEnd(nums, start, mid, target),
searchStart(nums, mid, end, target)
];
} else if (nums[mid] < target) {
start = mid + 1;
} else {
end = mid - 1;
}
}
return [-1, -1];
};
module.exports = searchRange;