Skip to content

Latest commit

 

History

History
92 lines (74 loc) · 7.46 KB

File metadata and controls

92 lines (74 loc) · 7.46 KB

Item 14. Declare functions noexcept if they won't emit exceptions

Test Codes

Notes

During work on C++11, a consensus emerged that the truly meaningful information about a function's exception-emitting behavior was whether it had any.

  • I.e. black or white, either a function might emit an exception or it guaranteed that it wouldn't.
  • This maybe-or-never dichotomy forms the basis of C++11's exception specifications, which essentially replace C++98's. (C++98-style exception specifications, throw(), remain valid, but they're deprecated.)
  • In C++11, unconditional noexcept is for functions that guarantee they won't emit exceptions.

Advantages

  • Whether a function should be so declared with noexcept is a matter of interface design.

    • Whether a function is noexcept is as important a piece of imformation as whether a member function is const.
    • Failure to declare a function noexcept when you know that it won't emit an exception is simply poor interface specification.
  • Applying noexcept to functions permits compilers to generate better object code.

    • If, at runtime, an exception leaves f, f's exception specification is violated.
      • With the C++98 exception specification, the call stack is unwound to f's caller, and, after some actions not relevant here, program execution is terminated.
      • With the C++11 exception specification, runtime behavior is slightly different: the stack is only possibly unwound before program execution is terminated.
    • The difference between unwinding the call stack and possibly unwinding it has a surprisingly large impact on code generation.
      • In a noexception function, optimizers need not keep the runtime stack in an unwindable state if an exception would propagate out of the function, nor must they ensure that objects in a noexcept function are destoryed in the inverse order of construction should an exception leave the function.
      • Functions with throw() exception specifications lack such optimization flexibility, as do functions with no exception specification at all.
    int f(int x);           // no guarantee for exceptions. less optimizable

    int f(int x) throw();   // no exceptions from f: C++98 style. less optimizable

    int f(int x) noexcept;  // no exceptions from f: C++11 style. most optimizable
  • Declare noexcept possible to improve performance
    • In C++11, the copy operations inside std::vector::push_back can be silently replaced with moves unless it's known that the move operations won't emit exceptions.
      • The copy operations inside std::vector::push_back occurs when capacity is insufficient for a new element.
      • In that case, having moves replace copies would be safe, and the only side affect would be improved performance.
      • std::vector::push_back takes advantage of this "move if you can, but copy if you must" strategy, and it's not the only function in the Standard Library that does(e.g., std::vector::reserve, std::deque::insert, etc.)
      • They check to see if the operation is declared noexcept.
    • swap functions comprise another case where noexcept is particularly desirable.
      • Whether swaps in the Standard Library are noexcept is sometimes dependent on whether user-defined swaps are noexcept.
      • The fact that swapping higher-level data structures can generally be noexcept only if swapping their lower-level constituents is noexcept should motivate you to offer noexcept swap functions whenever you can.
    // These functions are conditionally noexcept: 
    //    whether they're noexcept depends on whether the expressions inside the noexcept clauses are noexcept. 

    template<class T, size_t N>
    void swap(T (&a)[N], T (&b)[N]) noexcept(noexcept(swap(*a, *b)));

    template<class T1, class T2>
    struct pair {
        void swap(pair& p) noexcept(noexcept(swap(first, p.first)) && 
                                    noexcept(swap(second, p.second)));
        //...
    }

Make sure correctness

  • Declare a function noexcept only if you're willing to commit to a noexcept implementation over the long term.

  • The fact of the matter is that most functions are exception-neutral.

    • Such functions throw no excetpions themselves, but functions they call might emit one.
    • Exception-netural functions are never noexcept, because they may emit such "just passing through" exceptions.
  • Some functions, however, have natural implementations that emit no exceptions, and for a few more - notably the move operations and swap - being noexcept can have such a significant payoff, it's worth implementing them in a noexcept manner if at all possible.

    • But if a straightforward function implementation might yield exceptions(e.g., by invoking a function that might throw), the hoops you'll jump through to hide that from callers(e.g., catching all exceptions and replacing them with status codes or speical return values) will not only complicate your function's implementation, it will typically complicate code at call sites, too. That'd be poor software engineering.
  • For some functions, being noexcept is so important, they're that way by default.

    • In C++11, by default, all memory deallocation functions and all destructors - both user-defined and compiler-generated - are implicitly noexcept.
      • (There's thus no need to declare them noexcept. Declaring them noexcept explicity doesn't hurt anything, it's just unconventional.)
    • The only time a destructor is not implicity noexcept is when a data member of the class(including inherited members and those contained inside other data members) is of a type that expressly states that its destructor may emit exceptions(e.g., declares it noexcept(false)).
      • Such destructors are uncommon.
      • There're none in the Standard Library, and if the destructor for an object being used by the Standard Library(e.g., because it's in a container or was passed to an algorithm) emits an exception, the behavior of the program is undefined.
  • wide contract vs. narrow contract

    • It's worth noting that some library interface designers distinguish functions with wide contracts from those with narrow contracts.
      • A function with a wide contract has no preconditions(e.g., it imposes no constraints on the arguments that callers pass it.).
        • It never exhibit undefined behavior.
        • Easy to follow above advices and declaring it noexcept.
      • Functions without wide contract have narrow contracts.
        • If a precondition is violated, results are undefined.
        • Sometimes may need to throw exception if precondition violated. If so, it can't be declared with noexcept.
    // E.g., the f is wide contract and we know thiat t will never emit exception, so declare it `noexcept` will good to go.    
    void f(const std::string& s) noexcept;  

    // But if f requires precondition: s.length() <= 32, then it's narrow contract. 
    // Possibly a precondition checking will at the beginning of f, and hope to throw a "precondition was violated" exception if it happens.     
    void f(const std::string& s) ;  

References