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LifeCycleModel25.m
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%% Life-Cycle Model 25: Using Names for Permanent Types: patient and impatient
% Builds on Life-Cycle Model 11.
% Two permanent types of agent we will call 'patient' and 'impatient'
% Only difference is the value of beta, the discount factor parameter.
%
% We can treat the permanent types by name, and then VFI Toolkit will do
% everything based on these agent permanent type names.
%
% To compute the agent distribution we need to say how many agents are of
% each type. We denote this 'betadist' and it is a vector of weights that
% sum to one (we need to put the name of this in PTypeDistParamNames, like
% we would for a discount factor in DiscountFactorParamNames).
%
% All the commands we run look slightly different as they are the PType
% versions of the commands until now. Permanent types are much more
% powerful than just fixed-effects, and later models will show more options.
%
% Model statistics, like the life-cycle profiles we calculate here, are
% reported both for each permanent type (that is to say, conditional on the
% permanent type), and 'grouped' across the permanent types. Notice how
% VFI Toolkit automatically uses the names we gave the permanent types when
% generating results.
%
% Compared to Life-Cycle Model 24:
% We use Names_i everywhere we had N_i.
% Names_i contains the two names of our agents.
% The only difference between the two agents is their value of the discount factor parameter beta.
%% How does VFI Toolkit think about this?
%
% One decision variable: h, labour hours worked
% One endogenous state variable: a, assets (total household savings)
% Two stochastic exogenous state variables: z and e, persistent and transitory shocks to labor efficiency units, respectively
% Age: j
% Permanent types: i (called 'patient' and 'impatient')
%% Begin setting up to use VFI Toolkit to solve
% Lets model agents from age 20 to age 100, so 81 periods
Params.agejshifter=19; % Age 20 minus one. Makes keeping track of actual age easy in terms of model age
Params.J=100-Params.agejshifter; % =81, Number of period in life-cycle
% Grid sizes to use
n_d=51; % Endogenous labour choice (fraction of time worked)
n_a=201; % Endogenous asset holdings
n_z=21; % Exogenous labor productivity units shocks, persistent and transitiory
n_e=3;
Names_i={'patient','impatient'}; % Permanent type of agents
N_j=Params.J; % Number of periods in finite horizon
%% The parameter that depends on the permanent type
% Discount rate
Params.beta.patient = 0.96;
Params.beta.impatient = 0.9;
% Note that the impatient types value the future less (hence the choice of names)
%% How many of each permanent type are there
PTypeDistParamNames={'betadist'};
Params.betadist=[0.6,0.4]; % Must sum to one
% Note: implicitly, these weights are in the same order as Names_i
% Note: this is not relevant to solving the value function, but is needed for
% stationary distribition. It then gets encoded into the StationaryDist and
% so is not needed for things like life-cycle profiles.
%% Parameters
% Params.beta has been declared above
% Preferences
Params.sigma = 2; % Coeff of relative risk aversion (curvature of consumption)
Params.eta = 1.5; % Curvature of leisure (This will end up being 1/Frisch elasty)
Params.psi = 10; % Weight on leisure
% Prices
Params.w=1; % Wage
Params.r=0.05; % Interest rate (0.05 is 5%)
% Demographics
Params.agej=1:1:Params.J; % Is a vector of all the agej: 1,2,3,...,J
Params.Jr=46;
% Pensions
Params.pension=0.3;
% Age-dependent labor productivity units
Params.kappa_j=[linspace(0.5,2,Params.Jr-15),linspace(2,1,14),zeros(1,Params.J-Params.Jr+1)];
% persistent AR(1) process on idiosyncratic labor productivity units
Params.rho_z=0.9;
Params.sigma_epsilon_z=0.02;
% transitiory iid normal process on idiosyncratic labor productivity units
Params.sigma_epsilon_e=0.2; % Implictly, rho_e=0
% Conditional survival probabilities: sj is the probability of surviving to be age j+1, given alive at age j
% Most countries have calculations of these (as they are used by the government departments that oversee pensions)
% In fact I will here get data on the conditional death probabilities, and then survival is just 1-death.
% Here I just use them for the US, taken from "National Vital Statistics Report, volume 58, number 10, March 2010."
% I took them from first column (qx) of Table 1 (Total Population)
% Conditional death probabilities
Params.dj=[0.006879, 0.000463, 0.000307, 0.000220, 0.000184, 0.000172, 0.000160, 0.000149, 0.000133, 0.000114, 0.000100, 0.000105, 0.000143, 0.000221, 0.000329, 0.000449, 0.000563, 0.000667, 0.000753, 0.000823,...
0.000894, 0.000962, 0.001005, 0.001016, 0.001003, 0.000983, 0.000967, 0.000960, 0.000970, 0.000994, 0.001027, 0.001065, 0.001115, 0.001154, 0.001209, 0.001271, 0.001351, 0.001460, 0.001603, 0.001769, 0.001943, 0.002120, 0.002311, 0.002520, 0.002747, 0.002989, 0.003242, 0.003512, 0.003803, 0.004118, 0.004464, 0.004837, 0.005217, 0.005591, 0.005963, 0.006346, 0.006768, 0.007261, 0.007866, 0.008596, 0.009473, 0.010450, 0.011456, 0.012407, 0.013320, 0.014299, 0.015323,...
0.016558, 0.018029, 0.019723, 0.021607, 0.023723, 0.026143, 0.028892, 0.031988, 0.035476, 0.039238, 0.043382, 0.047941, 0.052953, 0.058457, 0.064494,...
0.071107, 0.078342, 0.086244, 0.094861, 0.104242, 0.114432, 0.125479, 0.137427, 0.150317, 0.164187, 0.179066, 0.194979, 0.211941, 0.229957, 0.249020, 0.269112, 0.290198, 0.312231, 1.000000];
% dj covers Ages 0 to 100
Params.sj=1-Params.dj(21:101); % Conditional survival probabilities
Params.sj(end)=0; % In the present model the last period (j=J) value of sj is actually irrelevant
% Warm glow of bequest
Params.warmglow1=0.3; % (relative) importance of bequests
Params.warmglow2=3; % bliss point of bequests (essentially, the target amount)
Params.warmglow3=Params.sigma; % By using the same curvature as the utility of consumption it makes it much easier to guess appropraite parameter values for the warm glow
%% Grids
% The ^3 means that there are more points near 0 and near 10. We know from
% theory that the value function will be more 'curved' near zero assets,
% and putting more points near curvature (where the derivative changes the most) increases accuracy of results.
a_grid=10*(linspace(0,1,n_a).^3)'; % The ^3 means most points are near zero, which is where the derivative of the value fn changes most.
% First, the AR(1) process z
if Params.rho_z<0.99
[z_grid,pi_z]=discretizeAR1_FarmerToda(0,Params.rho_z,Params.sigma_epsilon_z,n_z);
elseif Params.rho_z>=0.99 % Rouwenhourst performs better than Farmer-Toda when the autocorrelation is very high
[z_grid,pi_z]=discretizeAR1_Rouwenhorst(0,Params.rho_z,Params.sigma_epsilon_z,n_z);
end
z_grid=exp(z_grid); % Take exponential of the grid
[mean_z,~,~,~]=MarkovChainMoments(z_grid,pi_z); % Calculate the mean of the grid so as can normalise it
z_grid=z_grid./mean_z; % Normalise the grid on z (so that the mean of z is 1)
% Now the iid normal process e
[e_grid,pi_e]=discretizeAR1_FarmerToda(0,0,Params.sigma_epsilon_e,n_e);
e_grid=exp(e_grid); % Take exponential of the grid
pi_e=pi_e(1,:)'; % Because it is iid, the distribution is just the first row (all rows are identical). We use pi_e as a column vector for VFI Toolkit to handle iid variables.
mean_e=pi_e'*e_grid; % Because it is iid, pi_e is the stationary distribution (you could just use MarkovChainMoments(), I just wanted to demonstate a handy trick)
e_grid=e_grid./mean_e; % Normalise the grid on z (so that the mean of e is 1)
% To use e variables we have to put them into the vfoptions and simoptions
vfoptions.n_e=n_e;
vfoptions.e_grid=e_grid;
vfoptions.pi_e=pi_e;
simoptions.n_e=vfoptions.n_e;
simoptions.e_grid=vfoptions.e_grid;
simoptions.pi_e=vfoptions.pi_e;
% Grid for labour choice
h_grid=linspace(0,1,n_d)'; % Notice that it is imposing the 0<=h<=1 condition implicitly
% Switch into toolkit notation
d_grid=h_grid;
%% Now, create the return function
DiscountFactorParamNames={'beta','sj'};
% Notice: just uses LifeCycleModel11_ReturnFn.
ReturnFn=@(h,aprime,a,z,e,w,sigma,psi,eta,agej,Jr,pension,r,kappa_j,warmglow1,warmglow2,warmglow3,beta,sj) LifeCycleModel11_ReturnFn(h,aprime,a,z,e,w,sigma,psi,eta,agej,Jr,pension,r,kappa_j,warmglow1,warmglow2,warmglow3,beta,sj)
%% Now solve the value function iteration problem, just to check that things are working before we go to General Equilbrium
disp('Test ValueFnIter')
tic;
vfoptions.verbose=1; % Just so we can see feedback on progress
[V, Policy]=ValueFnIter_Case1_FHorz_PType(n_d,n_a,n_z,N_j,Names_i, d_grid, a_grid, z_grid, pi_z, ReturnFn, Params, DiscountFactorParamNames, vfoptions);
toc
% V is now a structure containing the value function for each permanent type
V
% So for example for permanent type 1, V_i(a,z,e,j)
size(V.patient)
% Policy likewise depends on type, e.g.,
size(Policy.patient)
% which is the same as
[length(n_d)+length(n_a),n_a,n_z,n_e,N_j]
% The other permanent types are named according to Names_i, so in our current case is
% V.impatient
% The n_a,n_z,n_e,N_j represent the state on which the decisions/policys
% depend, and there is one decision for each decision variable 'd' and each
% endogenous state variable 'a', and one for the markov exogenous state variable
% 'z', and one for the markov exogenous state variable 'e'.
% The different permanent types, i, are essentially just seperate value function problems.
%% We won't plot the Value and Policy fn, but thinking out how you would might be a good way to check you understand the form of V and Policy
%% Now, we want to graph Life-Cycle Profiles
%% Initial distribution of agents at birth (j=1)
% Before we plot the life-cycle profiles we have to define how agents are
% at age j=1. We will give them all zero assets.
jequaloneDist=zeros([n_a,n_z,n_e],'gpuArray'); % Put no households anywhere on grid
jequaloneDist(1,floor((n_z+1)/2),floor((n_e+1)/2))=1; % All agents start with zero assets, and the median value of each shock
% Anything that is not made to depend on the permanent type is
% automatically assumed to be independent of the permanent type (that is,
% identical across permanent types). This includes things like the initial
% distribution, jequaloneDist
%% We now compute the 'stationary distribution' of households
% Start with a mass of one at initial age, use the conditional survival
% probabilities sj to calculate the mass of those who survive to next
% period, repeat. Once done for all ages, normalize to one
Params.mewj=ones(1,Params.J); % Marginal distribution of households over age
for jj=2:length(Params.mewj)
Params.mewj(jj)=Params.sj(jj-1)*Params.mewj(jj-1);
end
Params.mewj=Params.mewj./sum(Params.mewj); % Normalize to one
AgeWeightsParamNames={'mewj'}; % So VFI Toolkit knows which parameter is the mass of agents of each age
StationaryDist=StationaryDist_Case1_FHorz_PType(jequaloneDist,AgeWeightsParamNames,PTypeDistParamNames,Policy,n_d,n_a,n_z,N_j,Names_i,pi_z,Params,simoptions);
% Again, we will explain in a later model what the stationary distribution
% is, it is not important for our current goal of graphing the life-cycle profile
%% FnsToEvaluate are how we say what we want to graph the life-cycles of
% Like with return function, we have to include (h,aprime,a,z) as first
% inputs, then just any relevant parameters.
FnsToEvaluate.fractiontimeworked=@(h,aprime,a,z,e) h; % h is fraction of time worked
FnsToEvaluate.earnings=@(h,aprime,a,z,e,w,kappa_j) w*h*kappa_j*z*e; % w*kappa_j*h*z*e is the labor earnings
FnsToEvaluate.assets=@(h,aprime,a,z,e) a; % a is the current asset holdings
FnsToEvaluate.beta=@(h,aprime,a,z,e,beta) beta; % beta is the parameter that differs by type
FnsToEvaluate.agej=@(h,aprime,a,z,e,agej) agej;
% notice that we have called these fractiontimeworked, earnings and assets
% Have added beta so that we can see how this evaluates differently across the different permanent types of agents
%% Calculate the life-cycle profiles
AgeConditionalStats=LifeCycleProfiles_FHorz_Case1_PType(StationaryDist, Policy, FnsToEvaluate, Params,n_d,n_a,n_z,N_j,Names_i,d_grid, a_grid, z_grid, simoptions);
% By default, this includes both the 'grouped' statistics, like
% AgeConditionalStats.earnings.Mean
% Which are calculated across all permanent types of agents.
% And also the 'conditional on permanent type' statistics, like
% AgeConditionalStats.earnings.patient.Mean
%% Plot the life cycle profiles of earnings, both grouped and for each of the different permanent types
figure(1)
plot(1:1:Params.J,AgeConditionalStats.earnings.Mean)
hold on
plot(1:1:Params.J,AgeConditionalStats.earnings.patient.Mean)
plot(1:1:Params.J,AgeConditionalStats.earnings.impatient.Mean)
hold off
title('Life Cycle Profile: Labor Earnings (w*h*kappa_j*z*e)')
legend('Grouped',Names_i{1},Names_i{2})
% Just as an illustration, let's look at the values for beta
% This is included as it helps make clear what exactly is meant by
% 'grouped' and by the stats conditional on ptype.
figure(2)
plot(1:1:Params.J,AgeConditionalStats.beta.Mean)
hold on
plot(1:1:Params.J,AgeConditionalStats.beta.patient.Mean)
plot(1:1:Params.J,AgeConditionalStats.beta.impatient.Mean)
hold off
title('Life Cycle Profile: discount factor beta')
legend('Grouped',Names_i{1},Names_i{2})
% Notice that the grouped one is just the weighted mean of the individual
% ones. As can be seen from the following two numbers being the same.
AgeConditionalStats.beta.Mean(1)
sum([Params.beta.patient,Params.beta.impatient].*Params.betadist)
%% Note that if we want statistics for the distribution as a whole we could use
AllStats=EvalFnOnAgentDist_AllStats_FHorz_Case1_PType(StationaryDist, Policy, FnsToEvaluate, Params,n_d,n_a,n_z,N_j,Names_i,d_grid, a_grid, z_grid, simoptions);
% Which again includes both aggregate and conditional on permanent type statistics.
% 'AllStats' covers everything from the mean and standard deviation, to the
% lorenz curve, to quantiles.
% Print some output for a few things
fprintf('The mean asset holdings for the economy are %8.4f \n',AllStats.assets.Mean)
fprintf('The mean asset holdings for the patient agents are %8.4f (they are %8.4f fraction of all households) \n',AllStats.assets.patient.Mean,StationaryDist.ptweights(1))
fprintf('The mean asset holdings for the impatient agents are %8.4f (they are %8.4f fraction of all households) \n',AllStats.assets.impatient.Mean,StationaryDist.ptweights(2))
figure(3)
subplot(3,1,1); plot(AllStats.assets.LorenzCurve)
title('Lorenz curve of assets holdings for the economy')
subplot(3,1,2); plot(AllStats.assets.patient.LorenzCurve)
title('Lorenz curve of assets holdings amongst patient agents')
subplot(3,1,3); plot(AllStats.assets.impatient.LorenzCurve)
title('Lorenz curve of assets holdings amongst impatient agents')
% Because AllStats is a structure it is very easy to see all the other
% kinds of statistics that are calculated as part of it.
% If you only want, e.g., the mean, or the LorenzCurve (rather than
% AllStats) there are functions for that, like
% EvalFnOnAgentDist_AggVars_FHorz_Case1_PType()
% But the actual speed gains from this a rather minimal, relative to just using AllStats
% (Most of the run time is in getting the values of the function on the
% grid, only a small fraction is calculating the final statistics at the end)