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course-schedule-ii.cpp
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// There are a total of n courses you have to take, labeled from 0 to n-1.
//
// Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]
//
// Given the total number of courses and a list of prerequisite pairs, return the ordering of courses you should take to finish all courses.
//
// There may be multiple correct orders, you just need to return one of them. If it is impossible to finish all courses, return an empty array.
//
// Example 1:
//
//
// Input: 2, [[1,0]]
// Output: [0,1]
// Explanation: There are a total of 2 courses to take. To take course 1 you should have finished
// course 0. So the correct course order is [0,1] .
//
// Example 2:
//
//
// Input: 4, [[1,0],[2,0],[3,1],[3,2]]
// Output: [0,1,2,3] or [0,2,1,3]
// Explanation: There are a total of 4 courses to take. To take course 3 you should have finished both
// courses 1 and 2. Both courses 1 and 2 should be taken after you finished course 0.
// So one correct course order is [0,1,2,3]. Another correct ordering is [0,2,1,3] .
//
// Note:
//
//
// The input prerequisites is a graph represented by a list of edges, not adjacency matrices. Read more about how a graph is represented.
// You may assume that there are no duplicate edges in the input prerequisites.
//
//
class Solution {
public:
vector<int> findOrder(int numCourses, vector<pair<int, int>>& prerequisites) {
vector<vector<int>> inGraph(numCourses, vector<int>());
vector<vector<int>> outGraph(numCourses, vector<int>());
vector<int> ans;
vector<bool> okCourse(numCourses, true);
for (auto&& prerequisite : prerequisites) {
outGraph[prerequisite.first].push_back(prerequisite.second);
inGraph[prerequisite.second].push_back(prerequisite.first);
okCourse[prerequisite.first] = false;
okCourse[prerequisite.second] = false;
}
for (int i = 0; i < okCourse.size(); ++i) {
if (okCourse[i]) ans.push_back(i);
}
while (true) {
bool changed = false;
for (int i = 0; i < numCourses; ++i) {
if (okCourse[i]) continue;
if (inGraph[i].empty()) {
okCourse[i] = true;
ans.push_back(i);
for (int j = 0; j < outGraph[i].size(); ++j) {
changed = true;
auto it = find(std::begin(inGraph[outGraph[i][j]]), std::end(inGraph[outGraph[i][j]]), i);
if (it != std::end(inGraph[outGraph[i][j]])) {
inGraph[outGraph[i][j]].erase(it);
}
}
}
}
if (!changed) {
break;
}
}
for (int i = 0; i < numCourses; ++i) {
if (!okCourse[i]) return vector<int>();
}
reverse(ans.begin(), ans.end());
return ans;
}
};