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populating-next-right-pointers-in-each-node-ii.cpp
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populating-next-right-pointers-in-each-node-ii.cpp
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// Given a binary tree
//
//
// struct TreeLinkNode {
// TreeLinkNode *left;
// TreeLinkNode *right;
// TreeLinkNode *next;
// }
//
//
// Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL.
//
// Initially, all next pointers are set to NULL.
//
// Note:
//
//
// You may only use constant extra space.
// Recursive approach is fine, implicit stack space does not count as extra space for this problem.
//
//
// Example:
//
// Given the following binary tree,
//
//
// 1
// / \
// 2 3
// / \ \
// 4 5 7
//
//
// After calling your function, the tree should look like:
//
//
// 1 -> NULL
// / \
// 2 -> 3 -> NULL
// / \ \
// 4-> 5 -> 7 -> NULL
//
//
/**
* Definition for binary tree with next pointer.
* struct TreeLinkNode {
* int val;
* TreeLinkNode *left, *right, *next;
* TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {}
* };
*/
class Solution {
public:
void connect(TreeLinkNode *root) {
TreeLinkNode *current = root;
TreeLinkNode *prev = nullptr;
TreeLinkNode *next_level = nullptr;
while (current) {
if (current->left) {
if (prev) {
prev->next = current->left;
}
prev = current->left;
if (!next_level) {
next_level = current->left;
}
}
if (current->right) {
if (prev) {
prev->next = current->right;
}
prev = current->right;
if (!next_level) {
next_level = current->right;
}
}
if (current->next) {
current = current->next;
} else {
current = next_level;
next_level = nullptr;
prev = nullptr;
}
}
}
};