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Could you create a version of Base91 that exactly map to 13bits? #1

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DonaldTsang opened this issue Oct 23, 2015 · 0 comments
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@DonaldTsang
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I would like to have a B91 system where each 52b maps to exactly 4 char in base91. Is it possible?
2^13 in base91 is 90:2, that means everything from C" (90:2) to "" (90:90) should be invalid pairs.

I though Base91 will sometimes put 14bits into 2 characters due to "higher compression", and i wanted a version of base91 that WILL NOT switch between 13bit and 14bit blocks.

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