获取access_toekn失败之后抛出异常的地方，能够与其他地方统一使用下述这个 resolveResponse 返回数据

[Sky9th]

我用的环境

CentOS7.3 APACHE2.4
PHP 版本：7.0
overtrue/wechat 版本：4.0-devmaster
是否使用了框架？框架名称：TP5.0

问题及现象

overtrue\wechat\src\Kernel\AccessToken.php ---- line144

public function requestToken(array $credentials): array
    {
        $response = $this->sendRequest($credentials);
        $result = json_decode($response->getBody()->getContents(), true);

        if (empty($result[$this->tokenKey])) {
            throw new HttpException('Request access_token fail: '.json_encode($result, JSON_UNESCAPED_UNICODE), $response);
        }

        return $result;
}

希望这个获取access_toekn失败之后抛出异常的地方，能够与其他地方统一使用下述这个 resolveResponse 返回数据

protected function resolveResponse(ResponseInterface $response, string $type)
    {
        $response = Response::buildFromPsrResponse($response);

        switch ($type) {
            case 'collection':
                return $response->toCollection();
            case 'array':
                return $response->toArray();
            case 'object':
                return $response->toObject();
            case 'raw':
            default:
                $response->getBody()->rewind();
                if (class_exists($type)) {
                    return new $type($response);
                }

                return $response;
        }
    }

[overtrue]

@Sky9th

try {
    $token->requestToken($credentials);
} catch (\Exception $e) {
     $e->response; // \Psr\Http\Message\ResponseInterface|null
     $e->formattedResponse; //根据 response_type 格式化的结果
 }