Wrong display name for current interpreter

[syagev]

Environment data

• VS Code version: 1.29.1
• Extension version (available under the Extensions sidebar): 2018.11.0
• OS and version: Windows 10
• Python version (& distribution if applicable, e.g. Anaconda): 3.5.4
• Type of virtual environment used (N/A | venv | virtualenv | conda | ...): pipenv

Actual behavior

The status bar displays the current interpreter (the one in the venv created by pipenv) as Python 3.6.6 although the Python version is actually 3.5.4

Note that while the displayed version is wrong, everything else works correctly (i.e. linting and launching is performed with the selected interpreter, which is indeed 3.5.4 and not 3.6.6)

Expected behavior

The status bar and interpreter selector should display "Python 3.5.4 64-bit"

Steps to reproduce:

This was probably caused since I had a Python 3.6.6 venv in that same location before, so I'm guessing these steps will reproduce the issue but I'm not 100% sure.

1. Create folder "test"
2. Inside test run python3.6 -m pipenv install
3. Open vscode to folder "test"
4. Close vscode
5. Run python3.6 -m pipenv --rm
6. Run python3.5 -m pipenv install
7. Open vscode to folder "test"

Logs

Output for Python in the Output panel (View→Output, change the drop-down the upper-right of the Output panel to Python): Nothing relevant

Output from Console under the Developer Tools panel (toggle Developer Tools on under Help): https://pastebin.com/4xf0UWf4

[DonJayamanne]

Duplicate of #3406

[syagev]

Crap. I actually read that issue and somehow didn't realize it's the same one.