A bug when I call thetimeout function multiple times

[chanyyyy]

No description provided.

[chanyyyy]

After one time out call, the other calls which shouldn't timeout end to raise the Functiontimeout exception too.
For example:
`@func_set_timeout(3)
def capp(rtsp):
return cv2.VideoCapture(rtsp)

rtsp_list = [readable stream1, readable stream2, unreadable stream3, readable stream4, readable stream5...]
`
When recycling the parameters in the list, only stream1 and stream2 can correctly return the capture, while all the rest readable stream will be timeout just because they are visited later than the unreadable stream3 be.

I'm troubled with this problem, hope for your reply soon.
Thank you.

[kata198]

Can you provide a more complete example with what you are doing?
If you are using it like

results = []
for stream in rtsp_list:
try:
results.append( capp(stream) )
except FunctionTimedOut:
print ( "Do something here" )

then it should be fine, "results" will only contain the completed stream.
If you are doing this and still having issues, it's possible that the video capture tool you are using has some cleanup or similar which isn't getting executed upon early termination. I would try creating a new instance of the stream reading object for every iteration, or recreating it upon a function timeout.

If you can provide a clearer example that I could test, I might be able to provide further input.

[chanyyyy]

收到，谢谢。