Enforce consistent usage of destructuring assignment of props, state, and context (react/destructuring-assignment)
Rule can be set to either of always
or never
;
"react/destructuring-assignment": [<enabled>, 'always']
By default rule is set to always
enforce destructuring assignment. Examples of incorrect code for this rule:
const MyComponent = (props) => {
return (<div id={props.id} />)
};
const Foo = class extends React.PureComponent {
render() {
return <div>{this.context.foo}</div>;
}
};
Below pattern is correct:
const MyComponent = ({id}) => {
return (<div id={id} />)
};
const MyComponent = (props, context) => {
const { id } = props;
return (<div id={id} />)
};
const Foo = class extends React.PureComponent {
render() {
const { title } = this.context;
return <div>{title}</div>;
}
};
Examples of incorrect code for this rule, when configured with "never"
:
const MyComponent = ({id}) => {
return (<div id={id} />)
};
const MyComponent = (props) => {
const { id } = props;
return (<div id={id} />)
};
const Foo = class extends React.PureComponent {
render() {
const { title } = this.state;
return <div>{title}</div>;
}
};
and below pattern is correct:
const MyComponent = (props) => {
return (<div id={props.id} />)
};
const Foo = class extends React.PureComponent {
render() {
return <div>{this.state.title}</div>;
}
};
...
"react/destructuring-assignment": [<enabled>, "always", { "ignoreClassFields": <boolean>, "destructureInSignature": "always" | "ignore" }]
...
When configured with true
, the rule will ignore class field declarations. Examples of correct code for this rule:
class Foo extends React.PureComponent {
bar = this.props.bar
}
This option can be one of always
or ignore
. When configured with always
, the rule will require props destructuring happens in the function signature.
Examples of incorrect code for destructureInSignature: 'always'
:
function Foo(props) {
const {a} = props;
return <>{a}</>
}
Examples of correct code for destructureInSignature: 'always'
:
function Foo({a}) {
return <>{a}</>
}
// Ignores when props is used elsewhere
function Foo(props) {
const {a} = props;
useProps(props); // NOTE: it is a bad practice to pass the props object anywhere else!
return <Goo a={a}/>
}