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429.n-ary-tree-level-order-traversal.py
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429.n-ary-tree-level-order-traversal.py
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#
# @lc app=leetcode id=429 lang=python3
#
# [429] N-ary Tree Level Order Traversal
#
# https://leetcode.com/problems/n-ary-tree-level-order-traversal/description/
#
# algorithms
# Medium (70.65%)
# Likes: 3306
# Dislikes: 127
# Total Accepted: 273.7K
# Total Submissions: 387.3K
# Testcase Example: '[1,null,3,2,4,null,5,6]'
#
# Given an n-ary tree, return the level order traversal of its nodes' values.
#
# Nary-Tree input serialization is represented in their level order traversal,
# each group of children is separated by the null value (See examples).
#
#
# Example 1:
#
#
#
#
# Input: root = [1,null,3,2,4,null,5,6]
# Output: [[1],[3,2,4],[5,6]]
#
#
# Example 2:
#
#
#
#
# Input: root =
# [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
# Output: [[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]]
#
#
#
# Constraints:
#
#
# The height of the n-ary tree is less than or equal to 1000
# The total number of nodes is between [0, 10^4]
#
#
#
# @lc code=start
"""
# Definition for a Node.
class Node:
def __init__(self, val=None, children=None):
self.val = val
self.children = children
"""
class Solution:
def levelOrder(self, root: 'Node') -> List[List[int]]:
if not root:
return []
queue = [root]
res = []
while queue:
res.append([node.val for node in queue])
queue = [child for node in queue for child in node.children]
return res
# @lc code=end