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Proper super set is not equivalent of super set. In other words, if one == other, then one issuperset of other(just like Python set.issuperset method).
ifoneLen==0||oneLen==otherLen {
returnfalse
}
The text was updated successfully, but these errors were encountered:
code in basic/set
Proper super set is not equivalent of super set.
In other words, if one == other, then one issuperset of other(just like Python set.issuperset method).
The text was updated successfully, but these errors were encountered: