Given a string s which consists of lowercase or uppercase letters, return the length of the longest palindrome that can be built with those letters.
Letters are case sensitive, for example, "Aa" is not considered a palindrome here.
Example 1:
Input: s = "abccccdd"
Output: 7
Explanation: One longest palindrome that can be built is "dccaccd", whose length is 7.
Example 2:
Input: s = "a"
Output: 1
Explanation: The longest palindrome that can be built is "a", whose length is 1.
Constraints:
-
$1$ <= s.length <=$2000$ - s consists of lowercase and/or uppercase English letters only.
Problem can be found in here!
Solution1: Hash Table
def longestPalindrome(s: str) -> int:
memo = {}
for token in s:
try:
memo[token] += 1
except KeyError:
memo[token] = 1
longest_length = 0
odd_flag = False
for i in memo.values():
if i % 2 == 0:
longest_length += i
else:
odd_flag = True
longest_length += (i-1)
return longest_length + 1 if odd_flag else longest_length
Time Complexity:
Solution2: Set
def longestPalindrome(s: str) -> int:
memo = set()
for token in s:
try:
memo.remove(token)
except KeyError:
memo.add(token)
has_odd_number = len(memo) > 0
return len(s) - len(memo) + 1 if has_odd_number else len(s)
Time Complexity: