Deleting existing function does not work

[Juliusan]

It was possible to delete the function, that is implemented, using meck:delete in version 0.9.0, however in 0.9.1 this throws an error.

Reproduction Steps

1. Implement a module with some exported function:

-module(some_module).
-export([some_function/2]).
some_function(SomeArg1, SomeArg2) ->
    {ok, SomeArg1, SomeArg2}.

2. Delete the exported function using meck and check if it is still available to be called.

Expected behavior

This test should pass:

meck_delete_test() ->
    ok = meck:new(some_module, [passthrough]),
    ?assert(erlang:function_exported(some_module, some_function, 2)),
    ok = meck:delete(some_module, some_function, 2, true),
    ?assertNot(erlang:function_exported(some_module, some_function, 2)),
    ?assert(meck:validate([some_module])),
    ok = meck:unload([some_module]).

Observed behavior

The test fails, indicating that second call to function_exported is still true.

Versions

• Meck version: 0.9.1 (the test passes in 0.9.0)
• Erlang version: 24.3

[Alberdi]

Adding the non_strict flag makes the test above pass:

meck_delete_test() ->
    ok = meck:new(some_module, [passthrough, non_strict]),
    ?assert(erlang:function_exported(some_module, some_function, 2)),
    ok = meck:delete(some_module, some_function, 2, true),
    ?assertNot(erlang:function_exported(some_module, some_function, 2)),
    ?assert(meck:validate([some_module])),
    ok = meck:unload([some_module]).

I'm not sure about the exact semantics of combining passthrough with non_strict to know if this was a hidden "feature", or if this brings new problems. But this seems to work, at least, as a workaround.