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hi there ~
in the doc:
Debug's enable state is currently persisted by localStorage. Consider the situation shown below where you have worker:a and worker:b, and wish to debug both. You can enable this using localStorage.debug:
localStorage.debug = 'worker:*'
And then refresh the page.
is there a way to not refresh the page and make it work ?
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awaiting-responseThis issue or pull request is awaiting a user's responseThis issue or pull request is awaiting a user's responsequestionThis issue asks a question or requests usage supportThis issue asks a question or requests usage support