-
-
Notifications
You must be signed in to change notification settings - Fork 181
/
Copy pathsame-tree.py
71 lines (65 loc) · 1.43 KB
/
same-tree.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
# -*- coding:utf-8 -*-
# Given two binary trees, write a function to check if they are the same or not.
#
# Two binary trees are considered the same if they are structurally identical and the nodes have the same value.
#
# Example 1:
#
#
# Input: 1 1
# / \ / \
# 2 3 2 3
#
# [1,2,3], [1,2,3]
#
# Output: true
#
#
# Example 2:
#
#
# Input: 1 1
# / \
# 2 2
#
# [1,2], [1,null,2]
#
# Output: false
#
#
# Example 3:
#
#
# Input: 1 1
# / \ / \
# 2 1 1 2
#
# [1,2,1], [1,1,2]
#
# Output: false
#
#
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def isSameTree(self, p, q):
"""
:type p: TreeNode
:type q: TreeNode
:rtype: bool
"""
stack = [(p, q)]
while stack:
node1, node2 = stack.pop()
if not node1 and not node2:
continue
if None in (node1, node2) or node1.val != node2.val:
return False
if node1.val == node2.val:
stack.append((node1.left, node2.left))
stack.append((node1.right, node2.right))
return True