README_EN.md

1637. Widest Vertical Area Between Two Points Containing No Points

中文文档

Description

Given n points on a 2D plane where points[i] = [xi, yi], Return the widest vertical area between two points such that no points are inside the area.

A vertical area is an area of fixed-width extending infinitely along the y-axis (i.e., infinite height). The widest vertical area is the one with the maximum width.

Note that points on the edge of a vertical area are not considered included in the area.

 

Example 1:

​

Input: points = [[8,7],[9,9],[7,4],[9,7]]
Output: 1
Explanation: Both the red and the blue area are optimal.

Example 2:

Input: points = [[3,1],[9,0],[1,0],[1,4],[5,3],[8,8]]
Output: 3

 

Constraints:

• n == points.length
• 2 <= n <= 105
• points[i].length == 2
• 0 <= xi, yi <= 109

Solutions

Python3

class Solution:
    def maxWidthOfVerticalArea(self, points: List[List[int]]) -> int:
        points.sort()
        return max(b[0] - a[0] for a, b in pairwise(points))

Java

class Solution {
    public int maxWidthOfVerticalArea(int[][] points) {
        Arrays.sort(points, (a, b) -> a[0] - b[0]);
        int ans = 0;
        for (int i = 0; i < points.length - 1; ++i) {
            ans = Math.max(ans, points[i + 1][0] - points[i][0]);
        }
        return ans;
    }
}

C++

class Solution {
public:
    int maxWidthOfVerticalArea(vector<vector<int>>& points) {
        sort(points.begin(), points.end());
        int ans = 0;
        for (int i = 0; i < points.size() - 1; ++i) {
            ans = max(ans, points[i + 1][0] - points[i][0]);
        }
        return ans;
    }
};

Go

func maxWidthOfVerticalArea(points [][]int) (ans int) {
	sort.Slice(points, func(i, j int) bool { return points[i][0] < points[j][0] })
	for i, p := range points[1:] {
		ans = max(ans, p[0]-points[i][0])
	}
	return
}

func max(a, b int) int {
	if a > b {
		return a
	}
	return b
}

JavaScript

/**
 * @param {number[][]} points
 * @return {number}
 */
var maxWidthOfVerticalArea = function (points) {
    points.sort((a, b) => a[0] - b[0]);
    let ans = 0;
    let px = points[0][0];
    for (const [x, _] of points) {
        ans = Math.max(ans, x - px);
        px = x;
    }
    return ans;
};

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