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中文文档

Description

You are given a list of equivalent string pairs synonyms where synonyms[i] = [si, ti] indicates that si and ti are equivalent strings. You are also given a sentence text.

Return all possible synonymous sentences sorted lexicographically.

 

Example 1:

Input: synonyms = [["happy","joy"],["sad","sorrow"],["joy","cheerful"]], text = "I am happy today but was sad yesterday"
Output: ["I am cheerful today but was sad yesterday","I am cheerful today but was sorrow yesterday","I am happy today but was sad yesterday","I am happy today but was sorrow yesterday","I am joy today but was sad yesterday","I am joy today but was sorrow yesterday"]

Example 2:

Input: synonyms = [["happy","joy"],["cheerful","glad"]], text = "I am happy today but was sad yesterday"
Output: ["I am happy today but was sad yesterday","I am joy today but was sad yesterday"]

 

Constraints:

  • 0 <= synonyms.length <= 10
  • synonyms[i].length == 2
  • 1 <= si.length, ti.length <= 10
  • si != ti
  • text consists of at most 10 words.
  • All the pairs of synonyms are unique.
  • The words of text are separated by single spaces.

Solutions

Python3

class Solution:
    def generateSentences(self, synonyms: List[List[str]], text: str) -> List[str]:
        p = {}

        def find(x):
            if p[x] != x:
                p[x] = find(p[x])
            return p[x]

        for a, b in synonyms:
            p[a] = a
            p[b] = b
        for a, b in synonyms:
            p[find(a)] = find(b)

        s = defaultdict(set)
        for a, b in synonyms:
            s[find(a)].add(a)
            s[find(b)].add(b)
        res = []
        for word in text.split(' '):
            if word not in p:
                if not res:
                    res.append([word])
                else:
                    for a in res:
                        a.append(word)
            else:
                words = sorted(s[find(word)])
                if not res:
                    for b in words:
                        res.append([b])
                else:
                    res = [a + [b] for a in res for b in words]
        return [' '.join(sentence) for sentence in res]

Java

class Solution {
    private Map<String, String> p;

    public List<String> generateSentences(List<List<String>> synonyms, String text) {
        p = new HashMap<>();
        for (List<String> item : synonyms) {
            p.put(item.get(0), item.get(0));
            p.put(item.get(1), item.get(1));
        }
        for (List<String> item : synonyms) {
            p.put(find(item.get(0)), find(item.get(1)));
        }
        Map<String, Set<String>> s = new HashMap<>();
        for (List<String> item : synonyms) {
            String a = find(item.get(0)), b = find(item.get(1));
            s.computeIfAbsent(a, k -> new HashSet<>()).add(item.get(0));
            s.computeIfAbsent(b, k -> new HashSet<>()).add(item.get(1));
        }
        List<List<String>> all = new ArrayList<>();
        for (String word : text.split(" ")) {
            if (!p.containsKey(word)) {
                if (all.isEmpty()) {
                    List<String> t = new ArrayList<>();
                    t.add(word);
                    all.add(t);
                } else {
                    for (List<String> a : all) {
                        a.add(word);
                    }
                }
            } else {
                Set<String> words = s.get(find(word));
                if (all.isEmpty()) {
                    for (String b : words) {
                        List<String> t = new ArrayList<>();
                        t.add(b);
                        all.add(t);
                    }
                } else {
                    List<List<String>> t = new ArrayList<>();
                    for (List<String> a : all) {
                        for (String b : words) {
                            List<String> c = new ArrayList<>(a);
                            c.add(b);
                            t.add(c);
                        }
                    }
                    all = t;
                }
            }
        }
        List<String> res = new ArrayList<>();
        for (List<String> item : all) {
            res.add(String.join(" ", item));
        }
        Collections.sort(res);
        return res;
    }

    private String find(String x) {
        if (!Objects.equals(p.get(x), x)) {
            p.put(x, find(p.get(x)));
        }
        return p.get(x);
    }
}

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