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1154. Day of the Year

中文文档

Description

Given a string date representing a Gregorian calendar date formatted as YYYY-MM-DD, return the day number of the year.

 

Example 1:

Input: date = "2019-01-09"
Output: 9
Explanation: Given date is the 9th day of the year in 2019.

Example 2:

Input: date = "2019-02-10"
Output: 41

 

Constraints:

  • date.length == 10
  • date[4] == date[7] == '-', and all other date[i]'s are digits
  • date represents a calendar date between Jan 1st, 1900 and Dec 31th, 2019.

Solutions

Python3

class Solution:
    def dayOfYear(self, date: str) -> int:
        y, m, d = (int(s) for s in date.split('-'))
        v = 29 if y % 400 == 0 or (y % 4 == 0 and y % 100) else 28
        days = [31, v, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
        return sum(days[:m-1]) + d

Java

class Solution {
    public int dayOfYear(String date) {
        int y = Integer.parseInt(date.substring(0, 4));
        int m = Integer.parseInt(date.substring(5, 7));
        int d = Integer.parseInt(date.substring(8));
        int v = y % 400 == 0 || (y % 4 == 0 && y % 100 != 0) ? 29 : 28;
        int[] days = {31, v, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
        int ans = d;
        for (int i = 0; i < m - 1; ++i) {
            ans += days[i];
        }
        return ans;
    }
}

C++

class Solution {
public:
    int dayOfYear(string date) {
        int y = stoi(date.substr(0, 4));
        int m = stoi(date.substr(5, 2));
        int d = stoi(date.substr(8));
        int v = y % 400 == 0 || (y % 4 == 0 && y % 100) ? 29 : 28;
        int days[] = {31, v, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
        int ans = d;
        for (int i = 0; i < m - 1; ++i) {
            ans += days[i];
        }
        return ans;
    }
};

Go

func dayOfYear(date string) (ans int) {
	y, _ := strconv.Atoi(date[:4])
	m, _ := strconv.Atoi(date[5:7])
	d, _ := strconv.Atoi(date[8:])
	days := []int{31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
	if y%400 == 0 || (y%4 == 0 && y%100 != 0) {
		days[1] = 29
	}
	ans += d
	for _, v := range days[:m-1] {
		ans += v
	}
	return
}

JavaScript

/**
 * @param {string} date
 * @return {number}
 */
var dayOfYear = function (date) {
    const y = +date.slice(0, 4);
    const m = +date.slice(5, 7);
    const d = +date.slice(8);
    const v = y % 400 == 0 || (y % 4 == 0 && y % 100) ? 29 : 28;
    const days = [31, v, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];
    return days.slice(0, m - 1).reduce((a, b) => a + b, d);
};

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