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中文文档

Description

The complement of an integer is the integer you get when you flip all the 0's to 1's and all the 1's to 0's in its binary representation.

  • For example, The integer 5 is "101" in binary and its complement is "010" which is the integer 2.

Given an integer n, return its complement.

 

Example 1:

Input: n = 5
Output: 2
Explanation: 5 is "101" in binary, with complement "010" in binary, which is 2 in base-10.

Example 2:

Input: n = 7
Output: 0
Explanation: 7 is "111" in binary, with complement "000" in binary, which is 0 in base-10.

Example 3:

Input: n = 10
Output: 5
Explanation: 10 is "1010" in binary, with complement "0101" in binary, which is 5 in base-10.

 

Constraints:

  • 0 <= n < 109

 

Note: This question is the same as 476: https://leetcode.com/problems/number-complement/

Solutions

Python3

class Solution:
    def bitwiseComplement(self, n: int) -> int:
        if n == 0:
            return 1
        ans = 0
        find = False
        for i in range(30, -1, -1):
            b = n & (1 << i)
            if not find and b == 0:
                continue
            find = True
            if b == 0:
                ans |= 1 << i
        return ans

Java

class Solution {
    public int bitwiseComplement(int n) {
        if (n == 0) {
            return 1;
        }
        int ans = 0;
        boolean find = false;
        for (int i = 30; i >= 0; --i) {
            int b = n & (1 << i);
            if (!find && b == 0) {
                continue;
            }
            find = true;
            if (b == 0) {
                ans |= (1 << i);
            }
        }
        return ans;
    }
}

C++

class Solution {
public:
    int bitwiseComplement(int n) {
        if (n == 0) return 1;
        int ans = 0;
        bool find = false;
        for (int i = 30; i >= 0; --i) {
            int b = n & (1 << i);
            if (!find && b == 0) continue;
            find = true;
            if (b == 0) ans |= (1 << i);
        }
        return ans;
    }
};

Go

func bitwiseComplement(n int) int {
	if n == 0 {
		return 1
	}
	ans := 0
	find := false
	for i := 30; i >= 0; i-- {
		b := n & (1 << i)
		if !find && b == 0 {
			continue
		}
		find = true
		if b == 0 {
			ans |= (1 << i)
		}
	}
	return ans
}

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