README_EN.md

283. Move Zeroes

中文文档

Description

Given an integer array nums, move all 0's to the end of it while maintaining the relative order of the non-zero elements.

Note that you must do this in-place without making a copy of the array.

 

Example 1:

Input: nums = [0,1,0,3,12]
Output: [1,3,12,0,0]

Example 2:

Input: nums = [0]
Output: [0]

 

Constraints:

• 1 <= nums.length <= 104
• -231 <= nums[i] <= 231 - 1

 

Follow up: Could you minimize the total number of operations done?

Solutions

Python3

class Solution:
    def moveZeroes(self, nums: List[int]) -> None:
        """
        Do not return anything, modify nums in-place instead.
        """
        left, n = 0, len(nums)
        for right in range(n):
            if nums[right] != 0:
                nums[left], nums[right] = nums[right], nums[left]
                left += 1

Java

class Solution {
    public void moveZeroes(int[] nums) {
        int left = 0, n = nums.length;
        for (int right = 0; right < n; ++right) {
            if (nums[right] != 0) {
                int t = nums[left];
                nums[left] = nums[right];
                nums[right] = t;
                ++left;
            }
        }
    }
}

C++

class Solution {
public:
    void moveZeroes(vector<int>& nums) {
        int left = 0, n = nums.size();
        for (int right = 0; right < n; ++right) {
            if (nums[right] != 0) {
                swap(nums[left], nums[right]);
                ++left;
            }
        }
    }
};

Go

func moveZeroes(nums []int) {
	n := len(nums)
	left := 0
	for right := 0; right < n; right++ {
		if nums[right] != 0 {
			nums[left], nums[right] = nums[right], nums[left]
			left++
		}
	}
}

JavaScript

/**
 * @param {number[]} nums
 * @return {void} Do not return anything, modify nums in-place instead.
 */
var moveZeroes = function (nums) {
    let left = 0,
        n = nums.length;
    for (let right = 0; right < n; ++right) {
        if (nums[right]) {
            [nums[left], nums[right]] = [nums[right], nums[left]];
            ++left;
        }
    }
};

/**
 * @param {number[]} nums
 * @return {void} Do not return anything, modify nums in-place instead.
 */
var moveZeroes = function (nums) {
    let left = 0;
    let right = left;
    while (left < nums.length) {
        if (nums[left] != 0) {
            left++;
        } else {
            right = left + 1;
            while (right < nums.length) {
                if (nums[right] == 0) {
                    right++;
                } else {
                    let tem = nums[left];
                    nums[left] = nums[right];
                    nums[right] = tem;
                    break;
                }
            }
            left++;
        }
    }
};

TypeScript

/**
 Do not return anything, modify nums in-place instead.
 */
function moveZeroes(nums: number[]): void {
    const n = nums.length;
    let i = 0;
    for (let j = 0; j < n; j++) {
        if (nums[j]) {
            if (j > i) {
                [nums[i], nums[j]] = [nums[j], 0];
            }
            i++;
        }
    }
}

Rust

impl Solution {
    pub fn move_zeroes(nums: &mut Vec<i32>) {
        let mut i = 0;
        for j in 0..nums.len() {
            if nums[j] != 0 {
                if j > i {
                    nums[i] = nums[j];
                    nums[j] = 0;
                }
                i += 1;
            }
        }
    }
}

C

void moveZeroes(int *nums, int numsSize) {
    int i = 0;
    for (int j = 0; j < numsSize; j++) {
        if (nums[j] != 0) {
            if (j > i) {
                nums[i] = nums[j];
                nums[j] = 0;
            }
            i++;
        }
    }
}

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