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As a user, I expect that I will receive the best exchange result in case:
If I select [V3, V4] protocols
And if I add V2 from the previous set [V3, V4] -> [V2, V3, V4]
But the quote calculation with V2 in set gets worse.
I guess that if the liquidity in V2 does not get profit in quote, it should not be considered, as another protocols are already in set and have a better quote.
bandicam.2025-02-25.13-51-34-223.mp4
The text was updated successfully, but these errors were encountered:
Nikita-Polyakov
changed the title
[Bug] [V2 + V3 + V4] quote is worse than [V3 + V4] quote
[Bug] [V2, V3, V4] quote is worse than [V3, V4] quote
Feb 25, 2025
As a user, I expect that I will receive the best exchange result in case:
[V3, V4]
protocolsV2
from the previous set[V3, V4]
->[V2, V3, V4]
But the quote calculation with
V2
in set gets worse.I guess that if the liquidity in
V2
does not get profit in quote, it should not be considered, as another protocols are already in set and have a better quote.bandicam.2025-02-25.13-51-34-223.mp4
The text was updated successfully, but these errors were encountered: