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floydwarshall_geek.c
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#if 0
#include<stdio.h>
#define V 4
#define INF 99999
void printSolution(int dist[][V]);
void printSolution(int dist[][V])
{
printf ("Following matrix shows the shortest distances"
" between every pair of vertices \n");
int i;
int j;
for (i = 0; i < V; i++)
{
for (j = 0; j < V; j++)
{
if (dist[i][j] == INF)
printf("%7s", "INF");
else
printf ("%7d", dist[i][j]);
}
printf("\n");
}
}
void floydWarshell (int graph[][V])
{
int dist[V][V], i, j, k;
for (i = 0; i < V; i++)
for (j = 0; j < V; j++)
dist[i][j] = graph[i][j];
for (k = 0; k < V; k++)
{
for (i = 0; i < V; i++)
{
for (j = 0; j < V; j++)
{
if (dist[i][k] + dist[k][j] < dist[i][j])
dist[i][j] = dist[i][k] + dist[k][j];
}
}
}
printSolution(dist);
}
// driver program to test above function
int main()
{
/* Let us create the following weighted graph
10
(0)------->(3)
| /|\
5 | |
| | 1
\|/ |
(1)------->(2)
3 */
int graph[V][V] = { {0, 5, INF, 10},
{INF, 0, 3, INF},
{INF, INF, 0, 1},
{INF, INF, INF, 0}
};
// Print the solution
floydWarshell(graph);
return 0;
}
#endif
//#if 0
#include <stdio.h>
#define MAX 1000
int arr[MAX][MAX];
int dist[MAX][MAX];
int main()
{
int num;
int i;
int j;
int k;
int r;
int c;
printf("Welcome to Floyd Warshall..\n");
printf("Enter number of ndoes..\n");
scanf("%d", &num);
for(r=0; r < num; r++) {
for(c=0; c< num; c++) {
scanf("%d", &dist[r][c]);
}
}
for(k=0; k < num; k++) {
for(i=0; i < num; i++) {
for(j=0; j < num; j++) {
if ((dist[i][k] + dist[k][j]) < dist[i][j])
dist[i][j] = dist[i][k] + dist[k][j];
}
}
}
for (i = 0; i < num; i++)
{
for (j = 0; j < num; j++)
{
/*
if (dist[i][j] == 9999)
printf("%7s", "INF");
else
printf ("%7d", dist[i][j]);
*/
printf("[%d]", dist[i][j]);
}
printf("\n");
}
}
//#endif