deploy: Ohdmire/mywebsite@709530a

Author: Ohdmire

index.html

@@ -783,11 +783,11 @@ <h2 class="mt-0 mb-0 text-xl text-neutral-800 dark:text-neutral-300">
                         </div>
 
                     </div>
-                    <section class="prose dark:prose-invert"><div id="typeit-0-1700039218562708956"></div>
+                    <section class="prose dark:prose-invert"><div id="typeit-0-1700040276011214816"></div>
 
 <script>
     document.addEventListener("DOMContentLoaded", function () {
-      new TypeIt("#typeit-0-1700039218562708956", {
+      new TypeIt("#typeit-0-1700040276011214816", {
         strings: ["","The limits of my language mean the limits of my world.",""],
         speed:  100 ,
         lifeLike:  false ,

index.json

@@ -1323,8 +1323,8 @@ <h3 class="relative group">快速找到结束值
 <p>再代入回之前的万能公式<code>循环次数=(结束值-初始值)/步长+1</code>，那么就是</p>
 <div class="highlight"><pre tabindex="0" class="chroma"><code class="language-Python" data-lang="Python"><span class="line"><span class="cl"><span class="n">count</span><span class="o">=</span><span class="p">(</span><span class="mi">5</span><span class="o">-</span><span class="mi">50</span><span class="p">)</span><span class="o">/-</span><span class="mi">3</span><span class="o">+</span><span class="mi">1</span> <span class="c1">#count=16</span>
 </span></span></code></pre></div><p>当然你也可以直接让<code>循环次数=X+1</code>，因为<code>X</code>刚好是树木的间隔</p>
-<p>⚠️下面的方法是分类讨论，因为还有情况，就是判定条件中&gt;和≥
-如果你觉得列方程比较麻烦，你可以直接拿<code>(条件值-初始值)/步长</code>，得到一个数。</p>
+<p>⚠️下面的方法是分类讨论，因为还有情况，就是判定条件中<code>&gt;</code>和<code>≥</code></p>
+<p>如果你觉得列方程比较麻烦，你可以直接拿<code>(条件值-初始值)/步长</code>，得到一个数。</p>
 <ul>
 <li>如果是<strong>整数</strong>，且判定条件中<code>&gt;</code>，刚刚上面我设的<code>X</code>的值=<code>该整数-1</code></li>
 <li>如果是<strong>整数</strong>，且判定条件中<code>≥</code>，刚刚上面我设的<code>X</code>的值=<code>该整数</code></li>