[Swagger specification] skip the reference object property [OPENAPI 3.+]

[bmmule]

Swagger specification :

Consider in the case of "allOf" , i don't want to use one of the properties from my reference object , how should I achieve that?

example :

recipientAddress:
      allOf:
        - $ref: '#/components/schemas/Addresses'
Addresses:
      properties:
        addressCategory:
          type: string
          maxLength: 10
          description: Type of Address 
          enum: 
            - PERMANENT 
            - COMMUNICATON
          example: PERMANENT
        addressLine1:
          type: string
          maxLength: 40
          description: First line of the Address
          example: host tower

here i don't want property "addressCategory" in my object "recipientAddress".

[webron]

What's the point in cross posting here and #2116 (comment)? Also, when posting snippets, please make sure to use github's markdown otherwise it's hard to read your examples.

[webron]

You can't remove parts of an object when referencing it. If you want to reference only a part of it, you'd need to split Addresses into two objects and reference whichever part you need.

[bmmule]

In case my object has 20 properties and if i want to use 18 for other reference , i wanted to avoid duplication , is there any way to do it rather than having multiple copies?

[webron]

Separate the object into two, one with 18 properties, and the other with 2.

[bmmule]

ok , Thanks

[handrews]

answered, closing.