Array{Int,0}() doesn't work

[nalimilan]

0-dimensional arrays are inconsistent with other cases. The constructor would probably need to be adapted a bit.

julia> Array{Int,0}() 
ERROR: MethodError: no method matching Array{Int64,0}()
 in eval(::Module, ::Any) at ./boot.jl:236

julia> Array{Int,1}()
0-element Array{Int64,1}

julia> Array{Int,2}()
0x0 Array{Int64,2}

UPDATE: fixed according to comments

[yuyichao]

Note that Array{Int,0}(1) should NOT work. Array{Int,0}() should though.

[eschnett]

What @yuyichao is saying is that array constructors are different from most other collection constructors: They don't take a list of elements to initialize the array; instead, they always produce an uninitialized array. They accept integer arguments to specify the array size, and for a zero-dimensional array, they should accept zero integers.

[nalimilan]

Yes, of course. Though what's slightly annoying is that convert(Array{Int,0}, 1) and convert(Array{Int,1}, 1) don't work either. What's the shortest way to create a 0-dimensional array from a scalar?

[eschnett]

This syntax would be

let x=Array{Int}(); x[]=scalar; x end

If you find a way to avoid the local variable, let me know.

[nalimilan]

Yes, that's the shortest solution I could find. Is there a reason why convert is not supported?

[GunnarFarneback]

setindex!(Array(Int), scalar)

[nalimilan]

@GunnarFarneback Interesting one.

[JeffBezanson]

I like this game. Here's another one: fill(scalar, ()).

[eschnett]

On Sunday, April 17, 2016, Gunnar Farnebäck [email protected]
wrote:

setindex!(Array(Int), scalar)

This returns the scalar, not the array.

-erik

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[yuyichao]

This returns the scalar, not the array.

julia> setindex!(Array(Int), 1)
0-dimensional Array{Int64,0}:
1

The return value of setindex! has nothing to do with the return value of a[x] = b

[cstjean]

fill(scalar)