第 101 题：修改以下 print 函数，使之输出 0 到 99，或者 99 到 0 #158

yygmind · 2019-07-08T14:58:21Z

要求：

1、只能修改 setTimeout 到 Math.floor(Math.random() * 1000 的代码

2、不能修改 Math.floor(Math.random() * 1000

3、不能使用全局变量

function print(n){
  setTimeout(() => {
    console.log(n);
  }, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

The text was updated successfully, but these errors were encountered:

momodiy · 2019-07-08T16:04:20Z

function print(n){
  setTimeout((() => {
    console.log(n)
    return ()=>{}
  }).call(n,[]), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

Gentlemancj · 2019-07-09T01:10:42Z

function print(n){ setTimeout(() => { console.log(n); }, Math.floor(Math.random()+1) * 1000); } for(var i = 0; i < 100; i++){ print(i); }

ryanZiegler · 2019-07-09T01:17:35Z

function print(n){
  setTimeout(() => {
    console.log(n);
  }, 1, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

hzxfjmc · 2019-07-09T01:25:42Z

function print(n){
setTimeout((() => {
console.log(n);
}).apply(n), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
print(i);
}

dorseysen · 2019-07-09T01:37:19Z

第一种解法：

function print(n) {

    setTimeout( (() => {

        console.log(n);
    
    })(), Math.floor(Math.random() * 1000));
}


for(var i = 0; i < 100; i++){
    print(i);
}

另一种解法则是根据setTimeout的时间戳，只要让它按照时间戳顺序打印即可。但这样的时间耗时相当长。

function print(n){

    setTimeout(() => {
        
        setTimeout( () =>{
            console.log(n);
        }, 1000 * n);

    }, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
    print(i);
}

ramey502 · 2019-07-09T01:49:34Z

楼上匿名函数自执行是一种解法，直接利用表达式也是一种解法！

function print(n){
  setTimeout(console.log(n), Math.floor(Math.random() * 1000));
}

for(var i = 0; i < 100; i++) {
  print(i);
}

99到0，就是 99 - n

function print(n){
  setTimeout(console.log(99 - n), Math.floor(Math.random() * 1000));
}

for(var i = 0; i < 100; i++) {
  print(i);
}

defypro · 2019-07-09T01:59:12Z

综合上面各位大佬的答案，使用立即执行函数如果没有return值的话相当于

setTimeout(undefined, Math.floor(Math.random() * 1000));

浏览器会报错，所以还是需要加入返回值的

 setTimeout( (() => {
        console.log(n);
    	return ()=>{};
  })(), Math.floor(Math.random() * 1000));

luohong123 · 2019-07-09T02:09:27Z

依次打印出 0-99

function print(n){
  setTimeout(() => {
    setTimeout(()=>{
       console.log(n);
    },1000*n)
  }, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

依次打印出99-0

function print(n){
  setTimeout(() => {
    setTimeout(()=>{
       console.log(99-n);
    },1000*n)
  }, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

white-dew · 2019-07-09T02:16:18Z

function print(n){
  print.n === undefined ? (print.n = 0) : (n !== 0 && print.n + 1 !== n) ? (setTimeout(() => {print(n)}, 1000)) : (setTimeout(() => {
    console.log(n);
    print.n += 1
  }, Math.floor(Math.random() * 1000)))
}
for(var i = 0; i < 100; i++){
  print(i);
}

wwervin72 · 2019-07-09T02:17:00Z

综合上面大佬给出的答案，感觉这题就是打乱了输出顺序，根本解决办法无外乎就是让定时器里的函数在同一任务队列里去执行，立即执行函数可以实现，或者给任意只要相同的时间间隔也可以实现。

rongda · 2019-07-09T02:26:33Z

1、闭包，匿名函数自执行，即使创建它的上下文已经销毁，变量仍然存在，
2、是随机输出 0 到 99，或者 99 到 0？

liuzeyang · 2019-07-09T02:27:25Z

两种解法：

利用settimeout 接受多个参数的方向，将Math.floor(Math.random() * 1000)作为第三个参数，第二参数可以设置为任意值。
function print(n){
setTimeout(() => {
console.log(n);
}, 1, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
print(i);
}
2.可以利用settimeout 第一个参数可以是function是立即执行或者一个执行函数。

wineSu · 2019-07-09T02:28:55Z

综合上面各位大佬的答案，使用立即执行函数如果没有return值的话相当于
setTimeout(undefined, Math.floor(Math.random() * 1000));
浏览器会报错，所以还是需要加入返回值的
 setTimeout( (() => {
        console.log(n);
    	return ()=>{};
  })(), Math.floor(Math.random() * 1000));

没有报错啊

MoveZZG · 2019-07-09T02:36:44Z

忽略Math.floor(Math.random() * 1000) 影响（不过打印的太慢了吧(#`O′)）

function print(n){
setTimeout(() => {
setTimeout(()=>{
console.log(n);
},(n+1)*1000);
}, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
print(i);
}

nano-papa · 2019-07-09T02:38:54Z

综合上面各位大佬的答案，使用立即执行函数如果没有return值的话相当于
setTimeout(undefined, Math.floor(Math.random() * 1000));
浏览器会报错，所以还是需要加入返回值的
 setTimeout( (() => {
        console.log(n);
    	return ()=>{};
  })(), Math.floor(Math.random() * 1000));

window.setTimeout = function (vCallback, nDelay /*, argumentToPass1, argumentToPass2, etc. >*/) {
var oThis = this, aArgs = Array.prototype.slice.call(arguments, 2);
return __nativeST__(vCallback instanceof Function ? function () {
vCallback.apply(oThis, aArgs);
} : vCallback, nDelay);
};`

只是判断是不是function类型

Weathers0086 · 2019-07-09T02:40:46Z

function print(n){
setTimeout( (() => {
console.log(n);
return ()=>{};
})(), Math.floor(Math.random() * 1000));
}
for(var i=0;i<100;i++){
print(i)
}

kungithub · 2019-07-09T02:47:50Z

// 方法1 利用for的变量i  输出99-0
function print(n){
  setTimeout(() => {
    console.log(--i);
  }, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

//方法2 将setTimeout 的时间改为 0*Math.floor(Math.random() * 1000) .. 取巧了一下
// 输出0-99
function print(n){
  setTimeout(() => {
    console.log(n);
  }, 0*Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

824759494 · 2019-07-09T02:49:57Z

0-99

function print(n){
  setTimeout(() => {
    console.log(n);
  }, 1, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

99-0

function print(n){
  setTimeout(() => {
    console.log(99 - n);
  }, 1, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

supermanklk · 2019-07-09T02:51:57Z

function print(n){
setTimeout(() => {
console.log((i++)-100);
}, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
print(i);
}

FEJiuL · 2019-07-09T03:03:21Z

function print(n){
  setTimeout((n) => {
    console.log(n);
  },0,n, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

把Math.random挤掉就好了。

5SSS · 2019-07-09T03:07:30Z

0 -99
function print(n){
  setTimeout((function () {
	console.log(n)
	return function () {}
  })(), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

99 - 0
function print(n){
  setTimeout((function () {
	console.log(Math.abs(n - 99))
	return function () {}
  })(), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

song-le-yi · 2019-07-09T03:14:27Z

emm，楼主不给答案讲解得嘛

supermanklk · 2019-07-09T03:18:41Z

emm，楼主不给答案讲解得嘛

我理解的讲一下,2种方法
1.立即执行函数
2.定时器第二位重新赋固定的值

james9527 · 2019-07-09T04:13:48Z

题目解析：向setTimeout() 传递一个函数时，该函数中的this指向跟你的期望可能不同，当前这些代码中包含的 this 关键字在非严格模式会指向window对象，严格模式下为undefined。此时可以借助call或apply去改变this指向，即可顺序打印出0到99（或倒序99到0）

function print(n){
  setTimeout((() => {
    // console.log(this.i); // 如果不借助call会打印出100次全局变量i，值都为100
    console.log(n); // 顺序打印出0~99(100个)
    console.log(99-n); // 倒序打印出99~0(100个)
  }).call(null, n), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++) {
  // console.log(i) // 0~99
  print(i); 
}
console.log(i) // 注意：此时i在全局window里可访问到，值为100

haipingzi · 2019-07-09T05:18:51Z

function print(n) {
setTimeout(async ()=>{
await new Promise((resolve, reject)=>{
setTimeout(()=>{
resolve(n)
},n*1000)
});
console.log(n)
},Math.floor(Math.random()*100))
}

for(var i=0;i<100;i++){
print(i)
}

haipingzi · 2019-07-09T05:20:00Z

利用异步函数也可以，这个简单直接

Chorer · 2019-07-09T05:32:24Z

// 方法1 利用for的变量i  输出99-0
function print(n){
  setTimeout(() => {
    console.log(--i);
  }, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

//方法2 将setTimeout 的时间改为 0*Math.floor(Math.random() * 1000) .. 取巧了一下
// 输出0-99
function print(n){
  setTimeout(() => {
    console.log(n);
  }, 0*Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

请问第二个方法不是异步的吗，最后为什么不是都打印99呢？

gongtiexin · 2019-07-09T05:32:49Z

function print(n) {
setTimeout(() => {
console.log(n);
}, n * 1001 + Math.floor(Math.random() * 1000));
}
for (var i = 0; i < 100; i++) {
print(i);
}
不知道这样违规没有 🌚

kungithub · 2019-07-09T06:31:22Z

// 方法1 利用for的变量i  输出99-0
function print(n){
  setTimeout(() => {
    console.log(--i);
  }, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

//方法2 将setTimeout 的时间改为 0*Math.floor(Math.random() * 1000) .. 取巧了一下
// 输出0-99
function print(n){
  setTimeout(() => {
    console.log(n);
  }, 0*Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

请问第二个方法不是异步的吗，最后为什么不是都打印99呢？

这是当做参数传到print方法的，正真执行print方法的时候i参数就是当时的i的值

liuliudaren · 2019-07-23T02:49:10Z

function print(n){
setTimeout((() => {
console.log(n)
})(), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
print(i);
}
将setTimeout的第一个参数改为自执行就可以了

felaofan · 2019-07-30T08:28:42Z

思路很清晰，把setTimeout的第二个参数改为n

function print(n){
  setTimeout(() => {
    console.log(n);
  },n, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

3N26 · 2019-08-02T04:08:38Z

function print(n){
setTimeout(() => {
setTimeout(() => {
console.log(n);
}, n*1000)
}, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
print(i);
}

BellaGuan · 2019-08-03T10:20:24Z

@Chenxinan 你这个只要把Math.floor(Math.random() * 1000)改成Math.floor(Math.random() * 10000)就不会按顺序输出0-99。

BellaGuan · 2019-08-03T10:26:01Z

@Hunterang 恩恩，感觉这题是想考核面试者在不用promise.all()的情况下，在并发100次请求后，如何把浏览器在不同时间点获取到的数据按原先的数据逻辑顺序输出。

my-illusion · 2019-08-14T02:37:59Z

helloyoucan · 2019-08-14T06:12:05Z

// 0~99
function print(n){
	setTimeout(() => {
	 	setTimeout(()=>{
	 		console.log(n);
	 	},n*1000)
	}, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
	print(i);
}

// 99-0
function print(n){
	setTimeout(() => {
	 	setTimeout(()=>{
	 		console.log(n);
	 	},(100-n)*1000)
	}, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
	print(i);
}

第二种，去掉setTimeout

function print(n){
	((() => {
	 	console.log(n);
	})(), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
	print(i);
}

daiyunchao · 2019-08-14T10:51:05Z

function print(n){
	setTimeout(()=>{
		console.log(n);
	},(n*1000)+Math.floor(Math.random()*1000))
}
for(var i=0;i<100;i++){
	print(i)
}

SoftwareEngineerPalace · 2019-08-27T15:01:56Z

function print(n){
  setTimeout((() => {
    console.log(n)
    return ()=>{}
  }).call(n,[]), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

理是？没看懂

renshunli · 2019-09-18T10:14:58Z

我去脑筋急转弯的题

yaodongyi · 2019-09-21T04:50:19Z

function print(n) {
  setTimeout((i => {
      console.log(i);
    })(i),Math.floor(Math.random() * 1000)
  );
}
for (var i = 0; i < 100; i++) {
  print(i);
}

lzxxxxx · 2019-10-11T07:02:52Z

看了各位的解法我觉得自己的解法跟闹着玩似的…… 在每一次执行前重写了 Math.random…………

function print(n){
  setTimeout((function(){
    Math.random = function(){
      return 0.1 * n;
    }
    return (() => {
    console.log(n);
  })})(), Math.floor(Math.random() * 1000));
}

aeolusheath · 2019-10-23T02:32:20Z

        //  方法一
        function print(n) {
          setTimeout(() => {
            // console.log(n);
            let i = n
            setTimeout(() => {
              console.log(i, 'ddd')
            }, n * 1000)
          },
            Math.floor(Math.random() * 1000)
          );
        }
        for (var i = 0; i < 100; i++) {
          print(i);
        }

        // 方法二
        function print(n) {
          setTimeout(() => {
            // console.log(n);
            setTimeout((i) => {
              console.log(i)
            }, n * 1000, n)
          },
            Math.floor(Math.random() * 1000)
          );
        }
        for (var i = 0; i < 100; i++) {
          print(i);
        }



        // 方法三  立即执行函数，相当于同步代码
        function print(n){
          setTimeout((()=>{
            console.log(n)
            return ()=>{}
          })(), Math.floor(Math.random() * 1000));
        }
        for(var i = 0; i < 100; i++){
          print(i);
        }

niannings · 2020-04-13T07:15:29Z

换一种思路

function print(n){
  setTimeout(() => {
    if (!print.cache) {
      print.cache = [];
      print.id = null;
    };
    print.cache.push(n);
    clearTimeout(print.id);
    print.id = setTimeout(() => {
      print.cache.sort((a, b) => a - b);
    	for (let num of print.cache) {
      	console.log(num);
      }
      delete print.id;
      delete print.cache;
      // 最长不过1000ms
    }, 1000);
  }, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
	print(i);
}

Murphycx94 · 2020-05-16T06:20:03Z

感觉无论是立即执行函数、表达式，还是用n去替代Math.random，脱离了题目本身的意义。所以考的是脑筋急转弯？

Murphycx94 · 2020-05-16T06:22:16Z

function print(n){
setTimeout(() => {
setTimeout(() => { console.log(n) }, n * 1000)
}, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
print(i);
}

alan1111 · 2020-07-01T08:05:13Z

crabkiller · 2020-09-09T15:13:26Z

支持原题中间隔随机时间 print 的版本

(() => {
  function print(n) {
    setTimeout(
        (() => {
        // const prev = i.__proto__.prev;
        const prev = print.prev;
        let resolver = () => {};
        // i.__proto__.prev = new Promise(resolve => {
        print.prev = new Promise(resolve => {
          resolver = resolve;
        });
        const exec = (delay) => {
          setTimeout(() => {
            console.log(n);
            resolver();
          }, delay);
        };

        return prev
          ? (delay) => {
            prev
              .then(exec.bind(null, delay))
              .then(() => {
                // if (i.__proto__.prev) {
                if (print.prev) {
                  // delete i.__proto__.prev;
                  delete print.prev;
                }
              });
          }
          : exec;
      })(),
      0,
      Math.floor(Math.random() * 1000)
    );
  }
  for (var i = 0; i < 100; i++){
    print(i);
  }
})()

XuedaoYuan · 2020-09-24T08:52:56Z

不知道这燕子算不算满足要求

function print(n) {
	setTimeout(() => {
		if (!print.index && print.index !== 0) {
			print.index = 99
		} else {
			print.index--
		}
		console.log(print.index)
	}, Math.floor(Math.random() * 1000))
}
for (var i = 0; i < 100; i++) {
	print(i)
}

xxleyi · 2020-10-31T08:56:44Z

还可以利用逗号表达式 :-)

但我实在搞不懂这题的目的是啥？

function print(n){
  setTimeout((console.log(n), () => null), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

auyo18 · 2020-11-10T18:57:00Z

function print(n) {
    setTimeout(() => {
      if (!print.list) print.list = []
      if (!print.timer)
        print.timer = setTimeout(() => {
          print.list.forEach(fn => fn())
        }, 1000)
      print.list[n] = () => console.log(n)
    }, Math.floor(Math.random() * 1000))
  }

  for (var i = 0; i < 100; i++) {
    print(i)
  }

blank1u · 2020-12-14T02:47:01Z

function print(n) {
    setTimeout((function () {
        console.log(n);
        return () => { }
    })(), Math.floor(Math.random() * 1000));
}
for (var i = 0; i < 100; i++) {
    print(i);
}

liaoqinwei · 2021-04-16T03:21:27Z

`function print(n) {
setTimeout(() => {
console.log(100 - i--);
}, Math.floor(Math.random() * 1000));
}

for (var i = 0; i < 100; i++) {
print(i);
}`

zhangtaolei · 2021-11-28T03:50:23Z

词法环境与闭包的联系：
静态作用域
动态作用域

function print(n){
  setTimeout((() => {
    console.log(n);
    return ()=>{}
  })(), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

Joker-Qu · 2022-01-16T06:36:36Z

function print(n){
setTimeout(() => {
console.log(n)
}, 0 , Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
print(i);
}

Lingdeqing · 2022-03-18T06:59:49Z

0~99

function print(n){
  setTimeout((() => {
    console.log(99);
      return () => {}
  })(), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

99~0

function print(n){
  setTimeout((() => {
    console.log(99-n);
      return () => {}
  })(), Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}

Yangfan2016 · 2022-08-10T11:14:09Z

利用 settimeout 的第一个参数可以传表达式的原理，绕过了随机的定时器执行

function print(n){
    setTimeout((console.log(n),()=>{}),Math.floor(Math.random()*1000));
}

for(var i = 0; i < 100; i++){
  print(i);
}

xiaobinniu · 2023-11-17T10:20:02Z

function print(n){
  setTimeout(() => {
    console.log(n);
  }, 1, Math.floor(Math.random() * 1000));
}
for(var i = 0; i < 100; i++){
  print(i);
}
```机智

rongda · 2023-11-17T10:20:23Z

你好，我已经收到你的来信！

yygmind added the 字节 label Jul 8, 2019

yygmind added the 编程题 label Dec 16, 2019

第 101 题：修改以下 print 函数，使之输出 0 到 99，或者 99 到 0 #158

第 101 题：修改以下 print 函数，使之输出 0 到 99，或者 99 到 0 #158

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0~99

99~0

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